Question

A simple pendulum performs S.H.M. about x = 0 with an amplitude a, and time period T. The speed of the pendulum at x = a/2 will be(a) $\pi\frac{a\sqrt{3}}{T}$(b) $\frac{\pi a\sqrt{3}}{2T}$(c) $\frac{\pi a}{T}$(d) $\frac{3\pi^{2} a}{T}$

Answer 1

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Answer 2

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