a simple pendulum takes 32 seconds to complete 20 oscillations full stop what is the time period of the pendulum
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Answered by
1
as we know that the time taken to complete one vibration is called timeperiod.
therefore,time period = time taken/oscillation
=32/20
=1.6 sec.
therefore,time period = time taken/oscillation
=32/20
=1.6 sec.
Answered by
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⭐⭐⭐⭐⭐ ANSWER ⭐⭐⭐⭐⭐
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❄❄ DETAILED CONCEPTION ❄❄
➡ A simple pendulum is a heavy point mass (known as bob) suspended from a rigid support by a massless and inextensible string.
➡ The term "Oscillations" refer to the number of complete to and fro motion of the bob of the pendulum. It is similar to vibration.
➡ The term "Frequency" refers to the number of oscillations made in one second by the bob of the pendulum.
➡ The term "Time period" means the total time taken to complete one oscillation.
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❄❄❄❄ SOLUTION ❄❄❄❄
In 32 seconds, no. of complete oscillations = 20
So, in one second, no. of complete oscillations = Frequency = 20/32 = 0.625 Hz.
Now, time period = 1/frequency
= (1/0.625) seconds
= 1.6 Seconds [ANSWER]
==================================
⭐⭐⭐ ALWAYS BE BRAINLY ⭐⭐⭐
==================================
==================================
❄❄ DETAILED CONCEPTION ❄❄
➡ A simple pendulum is a heavy point mass (known as bob) suspended from a rigid support by a massless and inextensible string.
➡ The term "Oscillations" refer to the number of complete to and fro motion of the bob of the pendulum. It is similar to vibration.
➡ The term "Frequency" refers to the number of oscillations made in one second by the bob of the pendulum.
➡ The term "Time period" means the total time taken to complete one oscillation.
==================================
❄❄❄❄ SOLUTION ❄❄❄❄
In 32 seconds, no. of complete oscillations = 20
So, in one second, no. of complete oscillations = Frequency = 20/32 = 0.625 Hz.
Now, time period = 1/frequency
= (1/0.625) seconds
= 1.6 Seconds [ANSWER]
==================================
⭐⭐⭐ ALWAYS BE BRAINLY ⭐⭐⭐
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