Question

A simple pendulum travels with the distance in centimetre in consecutive seconds are 16,12,9..how much distance will it travel before coming to rest?

Answer 1

Answer:

The distance traveled by the pendulum  before coming to rest =  64 centimetres.

Step-by-step explanation:

We can infer that this is a geometric progression.

Therefore let the first term be $a_{1}$ = 16

Therefore the second term $a_{2}$ = 12 = $a_{1}$ r  = 16r

therefore the common ratio, r = 12/16 = 0.75

Let the third term be $a_{3}$ = 9 = $a_{2}$ r = 12 r

therefore r  = 9 / 12  = 0.75   .... the common ratio is less than one

So we can see that is indeed a geometric progression.

The distance the pendulum will travel before coming to rest

will be the summation of the progression to infinity

therefore the total distance traveled  = $\frac{a_1}{1 - r} = \frac{16}{(1 - 0.75)} = 16 / 0.25 = 16 \times 4 = 64 centimeters$

Answer 2

The required distance would be 144 km.

Step-by-step explanation:

Since we have given that

Consecutive seconds are 16, 12, 9

So, we need to find the distance.

So, the distance would be

L.C.M. of 16, 12 and 9

= 144

So, the required distance would be 144 km.

# learn more:

A sound wave has a frequency of 2 kilohertz and wavelength of 45 centimetres it takes 4 second to travel calculate the distance it travels

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