Question

A tank which is cuboidal in shape has volumne 6.4 meter cube the length and breadth of the base are 2m and 1.6m respectively find the depth of the tank

Answer 1

$\huge\mathbb{SOLUTION:-}$

• Given :-

• The volume of cuboid =6.4cu.m

• Length=2m

• breadth=1.6m

• we have to find the height of tank

Now :-

$\boxed{\sf{Volume\:of\:cuboid=l\times b\times h}}$

$\sf\implies 6.4=2\times 1.6\times h\\ \\ \sf\implies 6.4=3.2\times h\\ \\ \sf\implies \cancel{\dfrac{6.4}{3.2}}=height\\ \\ \sf\implies height=2$

$\boxed{\sf{\purple{Depth\:of\:tank=2m}}}$

Answer 2

$\bf{\Huge{\boxed{\rm{\red{ANSWER\::}}}}}$

$\bf{Given}\begin{cases}\sf{A\:tank\:which\:is\:cuboidal\:shape\:has\:volume\:=\:6.4m^{3} }\\\\ \sf{Length\:of\:cuboidal\:tank\:=\:2m}\\\\\sf{Width\:of\:cuboidal\:tank\:=\:1.6m}\end{cases}}$

$\bf{\Large{\underline{\bf{To\:\:Find\::}}}}}}$

The depth of the tank.

$\bf{\Large{\underline{\tt{\pink{Explanation\::}}}}}$

We know that formula of the volume of cuboid:

$\leadsto\sf{\purple{Volume\:of\:cuboid\:=\:Length*width*height}}$

Let the depth of the tank be R.

A/q

$\longmapsto\rm{6.4\:=\:2\:*\:1.6\:*\:R}$

$\longmapsto\rm{6.4\:=\:3.2\:*R}$

$\longmapsto\rm{R\:=\:\frac{6.4*10}{3.2*10} }$

$\longmapsto\rm{R\:=\:\cancel{\frac{64}{32} }}$

$\longmapsto\rm{\pink{R\:=\:2}}$

Thus,

$\bf{\Large{\boxed{\tt{The\:depth\:of\:the\:tank\:is\:\:2m}}}}}$