a simple pendulum us making oscillations with it's bob immersed in a liquid of density 1/n times of bob? whta is it's time period.?
Answers
Answered by
0
Answer:
2πlng−−−√
2πl(1−1n)g−−−−−−−−√
2πlng−−−√
2πl(n−1)g−−−−−−−−√
Answer :
B
Solution :
As discussed in theory part
T=2πlg(1−ρσ)−−−−−−−−√
ρ=density of liquid
σ=density of bob material
Given ρ=σn
hence period is 2πl1−(1n)g−−−−−−−−√
Similar questions