a simple pendulumn completes 20 oscillations in 25s the time is measured with a stop watch of least count 0.1 s the error in the measurements of time is
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Answered by
155
Bonjour!
Least count (ΔT) = 0.1s
Total time taken for 20 oscillation (T) = 25s
Percentage error = ΔT/T × 100%
= 0.004 × 100%
= 0.4%
Hope this helps..:)
Least count (ΔT) = 0.1s
Total time taken for 20 oscillation (T) = 25s
Percentage error = ΔT/T × 100%
= 0.004 × 100%
= 0.4%
Hope this helps..:)
Answered by
1
= 0.4 %
is your answer
is your answer
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