a sin square X+b cos squareX=C,then tan squareX =?
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Step-by-step explanation:
asin²x+bcos²x=c
asin²x+b(1-sin²x)=c
(a-b)sin²x+b=c
(a-b)sin²x=c-b
sin²x=(c-b)/(a-b)
asin²x+bcos²x=c
a(1-cos²x)+bcos²x=c
(b-a)cos²x+a=c
(b-a)cos²x=c-a
Multiply minus on both sides
(a-b)cos²x=a-c
cos²x=(a-c)/(a-b)
tan²x=sin²x/cos²x
tan²x=(c-b)/(a-c)
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