Question

Q-29- if the momentum of a body is increased by 50% what will be the percentage increase in the kinetic energy of the body





Plzzzz solve these two problems ​

Answer 1

Answer:

125%

Explanation:

Kinetic energy, KE1= p^2/2m

Momentum , p is increased by 50% then p2=1.5p

KE2= (1.5p)^2/2m=2.25p^2/2m

Percentage change in KE

2.25p^2/2m-p^2/2m= 1.25p^2/2m

1.25p^2/2m/p^2/2m=1.25×100=125%

Answer 2

Answer:

answer of second answer is 125%

Explanation:

and answer of 1st is given in your picture