a 'sincome is 60% more than that of B by what percent B's income less than a
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let b income is 100 so a income is 60 percent more than b i.e 60/100x100= 60
so a income is 60+100 i.e 160
now b's income is 160 -100 i.e 60
so percentage of b's income is 60/100x100 i.e 60
I'm stupid to have realized now.... but the answer is correct.
so a income is 60+100 i.e 160
now b's income is 160 -100 i.e 60
so percentage of b's income is 60/100x100 i.e 60
I'm stupid to have realized now.... but the answer is correct.
Answered by
1
Let the B's income be 100.
Then, A's income = 100 + 60% of 100
= 100 + 60/100 × 100
= Rs. 160
Change in income = 160-100 = Rs. 60
Change % = change/original value × 100
= 60/100× 100
= 60%
Hence, B's income is 60% less than A.
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