A sinewave has a period (duration of one cycle) of 35 μs. What is its corresponding frequency, in kHz, expressed to 3 significant figures?If the frequency of this sinewave is now reduced by a factor of 2.5, using the value calculated above to 3 significant figures, what will be the new period? Express your answer in μs, to 3 significant figures.
Answers
Given : A sinewave has a period (duration of one cycle) of 35 μs.
he frequency of this sinewave is now reduced by a factor of 2.5,
To Find : corresponding frequency, in kHz, expressed to 3 significant figures
what will be the new period in μs, to 3 significant figures.
Explanation:
A sinewave has a period (duration of one cycle) of 35 μs.
Frequency = 1/ Time Period
Time Period = 35 μs = 35 x 10⁻⁶ s
=> Frequency = 1/ 35 x 10⁻⁶ Hz
=> Frequency = 10⁶ / 35 Hz
=> Frequency = 1000 x 1000 / 35 Hz
=> Frequency = 1000 / 35 kHz
=> Frequency = 200 / 7 kHz
=> Frequency = 28.57 kHz
=> Frequency = 28.6 kHz
the frequency of this sinewave is now reduced by a factor of 2.5
= New Frequency = 28.6/2.5 = 11.44 kHz
New Period = 1/ 11.44 x 10³ sec
=> New Period = 10⁶/ 11.44 x 10³ μs
=> New Period = 87.4 μs
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