Question

a single 12.0 V battery is connected in series with two identical 10 ohm resistors. What is the current moving through the first resistor

Answer 1

Answer:

current = .012 is the current moving thought the resistor

Answer 2

Given,

EMF of the battery = 12 V

Two resistors each of 10 Ω are connected in series.

To Find,

The current moving through the first resistor.

Solution,

The formula for calculating the equivalent resistance when resistors are connected in series is

R net = R₁+R₂

R net = 10 + 10

R net = 20 Ω

Now, using the ohm's law

V = RI

12 = 20*I

I = 12/20 = 0.6 amperes

Since both the resistors are connected in series so the current flowing through both the resistors will be the same.

Hence, the current flowing through the first resistor is 0.6 amperes.