Question

If a triangle has a base of 32/3cm and altitude of 63/4cm, find the area of the triangle?​

Answer 1

★ Given :-

• Base of Traingle = 32/3 cm
• altitude of Triangle = 63/4 cm

★ To Find :-

• area of the triangle ?

★ Solution :-

we know that,

$\boxed{ \bold { area \: of \: triangle = \frac{1}{2} \times base \times altitude }}$

$\bold{ \implies \frac{1}{2} \times \frac{ \cancel{32}}{ \cancel3} \times \frac{ \cancel{63}}{ \cancel4} } \\ \\ \bold{ \implies \frac{1}{ \cancel2} \times \cancel 8 \times 21 } \: \: \: \: \: \\ \\ \bold{ \implies 4 \times 21} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \bold{ \implies \underline{ \underline{84 \: {cm}^{2} }}} \: \: \: \: \: \: \: \: \: \: \: \: \:$

hence, area of the triangle is 84 cm²

Answer 2

Answer:

area of the triangle = 1/2* b* h

= 1/2* 63/4 * 32/3

$= 84cm {}^{2}$