Question

A single core cable used on 33000v has conductor diameter 10mm and the internal diameter of sheath 25mm.The maximum electrostatics stress in the cables is

Answer 1

Answer:

 72 x 105 V/m IS THE ANSWER

Answer 2

The maximum electrostatics stress in the cables is 6875 V/mm.

Explanation:

The maximum electrostatics stress in the cables is given as

$E=\frac{V}{r(ln\frac{R}{r}) }$

Here, R is the radius of cable( internal radius of the sheath) and r is the radius of conductor.

Given V = 33000 V, $R=\frac{25}{2}=12.5mm$ and $r=\frac{10mm}{2}=5mm$.

Substitute the values, we get

$E=\frac{33000}{5ln\frac{12.5}{5} }$

$E=\frac{33000}{5\times0.916}$

$E = 6875 V/ mm$

Thus, the maximum electrostatics stress in the cables is 6875 V/mm.

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