Question

A single phase, 50-Hz transformer has 80 turns on the primary winding and 400 turns on the secondary winding. The net cross-sectional area of the core is 200 cm2. If the primary winding is connected to 240-V, 50-Hz supply, determine (a) the emf induced in the secondary winding, and (b) the maximum flux density in the core.​

Answer 1

Answer:

50

Explanation:

not sure if the answer is anywhere correct

Answer 2

(a) emf induced in secondary winding = 1200 Volts

(b) Maximum flux density in core = 0.0135 Wb

Let,

V1 = Voltage supply to primary coil

V2 = Voltage rating of secondary coil

N1 = Number of turns of primary coil

N2 = Number of turns of secondary coil

f= frequency

Фmax = maximum flux density in the core

Emf induced in the secondary winding = Secondary voltage rating

∴ Emf2 = V1 × N2 / N1

∴ V2 or Emf2 = 240 × 400 / 80

∴ V2 = 1200 Volts

According to transformer equation,

V2 = 4.44 × f × N2 × Фmax

∴ Фmax = V2 / 4.44 × f × N2

∴ Фmax = 1200 / 4.44 × 50 × 400

∴ Фmax = 0.0135 Wb or 13.5 mWb