Question

a single phase neutral (spn) electrical circuit has a power consumption of 330w. considering a voltage of 110v and power factor of 0.8, the electrical current drawn is

Answer 1

We know that

P= VI........eq i


Given P and V is 330 and 110


putting in eq. i


330 = 110 A

A= 3 Ampere

Answer 2

Answer:

Current drawn, I = 3.75 A

Explanation:

Power consumption of the electrical circuit, P = 330 W

Power factor, $cos\ \theta=0.8$    

Voltage, V = 110 Volts

The ratio of real power to the apparent power that is applied to the circuit is called power factor of the circuit. Electrical power in terms of power factor is given by :

$P=VI\ cos\ \theta$

$I=\dfrac{P}{Vcos\ \theta}$

$I=\dfrac{330\ W}{110\ V\times 0.8}$

$I=3.75\ A$

The electrical current drawn is 3.75 A. Hence, this is the required solution.