Question

A single slit is of width 0.5 mm. Distance of screen
from slit is 1 m. Second maxima in diffraction
pattern is at distance 2 mm from centre. What is
wavelength of light?
(1) 560 nm
(2) 400 nm
(3) 40 nm
(4) 360 nm​

Answer 1

Answer:

560 nm

Explanation:

abhi foolow karo

Answer 2

Answer:

The wavelength of light is 400 nm .

Explanation:

Given that :

• Width of slit, d = 0.5 mm
• Distance of screen from slit, D = 1m
• Distance of second maximum from centre, x = 2 mm

Solution :

• The phenomen of bending of light around the corner of a small aperture and spreading into the region of geometrical shadow is called diffraction of light.
• Distance of n th secondary maxima from the centre of the screen is

$x(n) = (2n + 1) \frac{Dλ}{2d}$

• For second maxima n = 2.

$2 \times {10}^{ - 3} = (2 \times 2 + 1) \frac{λ}{2 \times 0.5 \times {10}^{ - 3} } \\ 2 \times {10}^{ - 3} = \frac{5λ}{ {10}^{ - 3} } \\ λ = \frac{2}{5} \times {10}^{ - 6} = 400nm$

• Hence, wavelength of light is 400 nm .