a siple pendulam takes 2o oscilation in 25 seconds then what will be the time period and frequency
Answers
Answered by
0
Answer:
The Time Period is 1.25 s and the Frequency is 0.8 Hz.
Explanation:
No. of oscillations done by a pendulum in 25 seconds = 20
No. of oscillations done by the pendulum in 1 second = [20/25] Hz
Frequency = 0.8 Hz
Time Period = 1/F
= 1/0.8 s
= 1.25 s
Hope this helps.
Answered by
6
Answer:
Given:
We have been given that number of oscillations of a simple pendulum is 20 and the time taken is 25 seconds.
To Find:
We need to find the time period and frequency of the pendulum.
Solution:
We know that the time period of a pendulum is given by:
Time taken by pendulum/number of oscillations.
Substituting the values, we have,
Time period = 20/25
= 4/5seconds
Now, frequency = 1/time period
= 1/(4/5)
= 1/4 × 5
= 5/4 Hertz
Hence, the time period of the pendulum is 4/5 seconds and frequency is 5/4hertz.
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