Question

A six digit no 4x4y96 is divisible by 88.Find the value of (x+2y)

Answer 1

Step-by-step explanation:

Given A six digit no 4x4y96 is divisible by 88. Find the value of (x+2y)

• Given a number to be divisible by 88, so that number is divisible by 8 and 11 also.
• Now applying divisibility rules we get
• For a number to be divisible by 8, the last three numbers need to be divisible by 8
• Here last 3 digits will be y96
• So y = 2 since 296 is divisible by 8
• So the number will be 4x4296
• Now for a number divisible by 11 we have sum of odd digits – sum of even digits need to be divisible by 11.
• So (4 + 4 + 9) – (x + 2 + 6)
• (17 – x ) – 8 should be divisible by 11.
• Therefore x = 9 which is divisible by 11
• So x = 9 and y = 2
• So x + 2y will be 9 + 2(2) = 9 + 4 = 13

Reference link will be

https://brainly.in/question/17420758