A six faced dice has three red faces two blue faces and one white face the die is rolled. Find the probability that the face that shows is (1)red(2) blue (3)white with solution
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6
number of red faces = 3
number of blue faces= 2
number of white faces= 1
total number of faces= 6
(1)
p(a)= number of trials in which event E has happened / total number of trials
= 3/6
=1/2
=0.5
(2)
p(a)= number of trials in which event E has happened / total number of trials
=2/6
=1/3
=0.3333
(3)
p(a)= number of trials in which event E has happened / total number of trials
=1/6
=0.1666
therefore the probability of getting a red face is 1/2 or 0.5, blue face is 1/3 or 0.3333 and white face is 1/6 or 0.1667
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3
even chance is probablity in which Red has more chance in the dice Blue has second largest change on dice and white has least chance on dife
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