A slab consists of two parallel layers of copper and brass of
the same thickness and having thermal conductivities in
the ratio 1 : 4. If the free face of brass is at 100°C and that of
copper at 0°C, the temperature of interface is
(a) 80°C (b) 20°C
(c) 60°C (d) 40°C
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As we know that conductive heat flow is given as Q=
L
KAΔT
and it is given that relation between thermal conductivity are as follow,
K
brass
=4K
copper
so,let an intermediate temperature T will line at inside the slab.
therefore,we equate the rate of heat flow from copper surface and brass surface,as follow
K
brass
(100−T)=K
copper
(T−0)
4(100−T)=T−0
T=80
0C
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If the free face of brass is at 100∘C and that of copper at 0∘C , the ... and brass of the same thickness and having thermal conductivities in the ratio 1:4. If ...
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