Question

A slab of ice 8 inches in length 11 inches and breadth and 2 inches thick was melted and greece holiday in the form of a rod of 8 inches diameter the length of such a rod in inches is nearest to

Answer 1

Answer:

3.5 inches

Step-by-step explanation:

Given that the slab of ice is 8 inches in length 11 inches and breadth and 2 inches thick.

Then, the volume of the slab ( cuboid) is

$V= L*W*H\\V= 8*11*2\\V=176 inch^3$

If the slab was melted and remade as a rod, Then the volume of the rod is equal to that of the slab.

The rod is cylindrical in shape and we are told that its diameter is 8 inches which means that it has a radius of 4 inches,

then its volume is computed as;

$V= \pi *r^2*l\\176= 3.142*4^2*l\\l=\frac{176}{3.142*4^2} \\\\l=3.500954806 inches$

and the length of the rod is 3.500954806 inches

Answer 2

Answer:

3.5 inches

Step-by-step explanation:

Given that the slab of ice is 8 inches in length 11 inches and breadth and 2 inches thick.

Then, the volume of the slab ( cuboid) is

If the slab was melted and remade as a rod, Then the volume of the rod is equal to that of the slab.

The rod is cylindrical in shape and we are told that its diameter is 8 inches which means that it has a radius of 4 inches,

then its volume is computed as;

and the length of the rod is 3.500954806 inches