Question

A slab of mass M is released from a height H on the top of a spring of
force constant K. The maximum compression of the spring is 'Y', then​

Answer 1

Answer:

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Answer 2

Answer:

mg(H+y) = 1/2 Ky^2

Explanation:

P.E lost in slab = P.E stored in the spring

Mg(H+y) = 1/2 Ky^2