Physics, asked by aruko9288, 7 months ago

A small air bubble of radius r in water is at depth h below the water surface. If P_0 is the atmospheric pressure, rho is the density of water and T is the surface tension of water, what is the pressure inside the bubble?

Answers

Answered by Anonymous

1

Answer:

Pressure just outside the bubble will be P+hdg

The 2T/r component is due to water-air interface surface tension and is additive because water exerts pressure on the bubble

So total pressure = P+hdg+2T/r

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