A small amount of xenon is present in the air. Several compounds of xenon have been made in recent years.
A compound of xenon contained 9.825g of xenon, 1.200g of oxygen and 5.700g of fluorine.
Determine the empirical formula of this compound.
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Answer:
XeOF4
Explanation:
1.first determine masses of compounds
xenon= 9.825g oxygen=1.2g flourine= 5.7 g
2. find moles of elements (moles= mass of element / Ar)
Xe= 9.825/131 = 0.075 mol
O = 1.2 / 16 = 0.075 mol
F = 5.7/19 = 0.3 mol
3. mole ratios (divide by smallest ratio)
Xe=0.075/0.075 = 1 Xe : O : F
O=0.075/0.075 =1 1 : 1 : 4
F= 0.3/0.075 =4
empirical formula
XeOF₄ (based on the ratios obtained above )
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