a small ball of relative density 0.8 falls into water from height of 2cm.the depth at which the ball will shink is
Answers
Answered by
3
Relative density = 0.8 = ρ(air)/ρ(water)
ρ(air)/ρ(water) = p/gh₁ / p /gh₂
0.8 = h₂/h₁
h₂ = 0.8 x h₁
h₂ = 0.8 x 2 x 10⁻²
h₂ = 1.6 cm
ρ(air)/ρ(water) = p/gh₁ / p /gh₂
0.8 = h₂/h₁
h₂ = 0.8 x h₁
h₂ = 0.8 x 2 x 10⁻²
h₂ = 1.6 cm
Similar questions