Physics, asked by Areeba6687, 1 year ago

A small block b is placed on another block a of mass 5 kg and 20 cm and initially the block b is near it and f block a constant force 10 newton is applied on block a all surfaces are frictionless time find time elapsing for the be separated from a

Answers

Answered by prabhas24480
1

given,

mass of block A , m = 5kg

from Newton's 2nd law,

F = ma

10 = 5a

a = 2m/s²

because there is no friction force between A and B. when the block A moves , block B remains at rest in its position.

take initial velocity of A, u = 0

distance to cover so that block B separate out, s = 0.2m

so, S = ut + 1/2at²

0.2 = 0 + 1/2 × 2 × t²

t² = 0.2

t = 0.45 sec

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