Math, asked by harshit6329, 1 year ago

What is the value of (a,y) in (13-20- a* 13y)= 168* 13-22?

Answers

Answered by webstar0
113
(13-20- 13ay)=168*13-22
= -7 -13ay = 2184-22
=-13ay = 2184+7-22
= -13 ay = 2169
= - ay = 2169/13
= ay = -166.8461....
Answered by phillipinestest
43

Answer: a < -8.2

Given that, (13 - 20 - a\times 13y) = 168 \times 13 - 22

As it has various identities in a single equation, we must use BODMAS,

BODMAS – Bracket Of Division, Multiplication, Addition and subtraction.

It follows as how the operation must be carried out in an equation, i.e. from division to Subtraction.

We get,

Divide both sides by 260.

The value of y is -8.265.

It is given that y > a. Therefore, the value of a is less than -8.2

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