A small block b is placed on block a of mass 1 kg and length 20 cm. if initially the block is placed at the right end of block
a. a constant horizontal force of 10 n is applied on the block
a. all the surfaces are assumed frictionless. find the time in which b separates from a
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let the mass of block b is mb....
force on lower block is F=10N....
accleration of system is a...
(mb+5)a = 10
a= 10/(mb+5) m/s2
now a seudo force acts on the upper block in opposite direction and its magnitude is f=(mb)a...
due to this force block moves in opposite direction with accleration a1....
mba1=mba
a1=a=10/(5+mb)
when the block covers a distance of 20cm then it separates out...
0.2 = a1t2/2
t2 = (0.4/a1)=[0.04(5+mb)]
t= 0.2(5+mb)1/2
force on lower block is F=10N....
accleration of system is a...
(mb+5)a = 10
a= 10/(mb+5) m/s2
now a seudo force acts on the upper block in opposite direction and its magnitude is f=(mb)a...
due to this force block moves in opposite direction with accleration a1....
mba1=mba
a1=a=10/(5+mb)
when the block covers a distance of 20cm then it separates out...
0.2 = a1t2/2
t2 = (0.4/a1)=[0.04(5+mb)]
t= 0.2(5+mb)1/2
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