Physics, asked by darkmystery, 7 months ago

A small block of super denae material haa maaa
3x1024 kg. It is situated at a height h(< <R) from
where it falls on the earth's surface. Ite speed when ita
n
height has reduced to (given mass of the earth la
6x10kg)
poh (b) on (0) zero​

Answers

Answered by mohit921
2

Answer:

B::C

Explanation:

Solution :

Given hltltltR <br> G mass

<br>

kg <br> let

velocity of earth <br>

velocity of the block <br> The two blocks are attached by gravittionl force of attrction. The gravitation potential energy stored will be the K.E. of two blocks <br> GM_em_b 1/(R+(h/2))=1/(R+h)

=(1/2)m_3xxv_2^2+(1/2)M_bxxv_b^2

M_eV_e=M_bV_b

rarr V_e=(M_bV_b)/M_e

Gm_exxm_b[2/(2R+h)-1/(R+h)]

=(1/2)xxM_exx(M_b^2V_b^2)/M_e^2+(1/2)xxM_bxxV_b^2

=(1/2)xxM_xxV_b^2 M_b/M_e+1/2xxM_bxxv_b^2

rarr GM_e (2R+2h-2R-h)/((2R+h)(R+h))

=(1/2)xxv_b^2xx((3x10^24)/(6x10^24)+1)

rarr [(GMxxh)/(2R^2)]=(1/2)xxV_b^2xx(3/2)

rarr gh=V_b^2xx(3/2)

V_b=(2gh)/3

I hope this answer will satisfy your needs

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