Math, asked by lipashaji54, 8 months ago

Prove that 1/1+sin theeta +1/1-sin theeta = 2 sec^2 theetta

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Answered by Anonymous
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Answer:

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Answered by tejasvi023
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to prove: 1/1-sintheta+1/1+sintheta=2sec^2theta

1/(1-sin)+1/(1+sin)=2sec

start with left side

LCD: (1-sin)(1+sin)=1-sin^2

=(1+sin+1-sin/1-sin^2

=2/(1-sin^2)

=2/cos^2

=2sec^2

verified:

left side=right side 

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