a small body of mass M = 0.1 kg at the end of chord of length one metre swings in a vertical circle its speed is 2 metre per second when the chord makes an angle theta = 30 degree with the vertical find tension in a chord
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Given:
The mass of the body is M=0.1 Kg
The speed of the body 2 m/sec
The angle is 30 °
To find:
The tension in the chord
Solution:
The tension is acting vertical which means there is centripetal force will be there also.
T=mv²/r +mgcosФ
Putting the above values
T=0.1×2²/1 + 0.1 ×10×√3/2
T=0.4+0.866
T=1.266 N
So, the tension in a chord is 1.266 N
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Answer:
1.266N
Explanation:
Given:
The mass of the body is M=0.1 Kg
The speed of the body 2 m/sec
The angle is 30 °
To find:
The tension in the chord
Solution:
The tension is acting vertical which means there is centripetal force will be there also.
T=mv²/r +mgcosФ
Putting the above values
T=0.1×2²/1 + 0.1 ×10×√3/2
T=0.4+0.866
T=1.266 N
So, the tension in a chord is 1.266 N
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