Question

a small body of mass M = 0.1 kg at the end of chord of length one metre swings in a vertical circle its speed is 2 metre per second when the chord makes an angle theta = 30 degree with the vertical find tension in a chord​

Answer 1

Given:

The mass of the body is M=0.1 Kg

The speed of the body 2 m/sec

The angle is 30 °

To find:

The tension in the chord

Solution:

The tension is acting vertical which means there is centripetal force will be there also.

T=mv²/r +mgcosФ

Putting the above values

T=0.1×2²/1 + 0.1 ×10×√3/2

T=0.4+0.866

T=1.266 N

So, the tension in a chord is 1.266 N

Answer 2

Answer:

1.266N

Explanation:

Given:

The mass of the body is M=0.1 Kg

The speed of the body 2 m/sec

The angle is 30 °

To find:

The tension in the chord

Solution:

The tension is acting vertical which means there is centripetal force will be there also.

T=mv²/r +mgcosФ

Putting the above values

T=0.1×2²/1 + 0.1 ×10×√3/2

T=0.4+0.866

T=1.266 N

So, the tension in a chord is 1.266 N