Physics, asked by thagadipallimanasa, 4 months ago

a small glass marble of mass m oscillates between the two edges, inside a hemispecial glass bowl of radius R if v is the speed of marble at the lowest position the normal reaction at that position is​

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Answered by bannybannyavvari
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Answer:

A small glass marble of mass m oscillates between the two edges, inside a hemispherical glass bowl of radius r . If 'V' is the speed of the marble at the ...

Top answer · 3 votes

At the highest point K.E. = 0, P.E = mgR At any intermediate point at angle theta: K.E. = m V^22 , P.E. = mgR ( 1 - Sin theta)

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