A small hole is made at the bottom of the
tank filled with water. If the total pressure
at the bottom of tank is 2 x 105 N/m2,
then the velocity of efflux is (1 atm = 105
N/m2)
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Answer:
Hey mate here is your answer.//
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Explanation:
1 atm=10 to the power 5 N/m², not 105 N/m²,
So,2×10 to the power 5 = 2 atm,
Net pressure at the bottom of the tank = 2 atm,
=> ρgh + 1 atm = 2 atm,
=> ρgh = 1 atm,
1 atm = 10⁵ N/m²,
density of water = 1000 kg/m³,
g = 10 m/s².
Putting these values in the eqn we get:
=> 1000 x 10 x h = 10⁵,
=> h = 10 m,
we know that the velocity of efflux is given by:
v =
=> v = √( 2 x 10 x 10),
=> v = 14.14 m/s.
Hence the velocity of efflux at the bottom will be 14.14 m/s.
Hope it helps you.//✔✔✔
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