Question

A small mass of 1 kg is attached to lower end of a string 1 m long whose upper end is
fixed. The mass is made to rotate in a horizontal circle of radius 0.6 m. If the circular
speed of the mass is constant, the tension in the string is ....
(1) 1.225 N
(2) 122.5 N
(3) 12.25 N
(4) 9.8 N​

Answer 1

Answer:

12.25 N

Explanation:

In the given diagram,

 sinθ = √1 - cos²θ = √1 - (0.6/1)²

         = √1 - 0.36 = 0.8

Note that,

Tsinθ = mg

T(0.8) = 1(9.8)

T = 9.8/0.8

T = 12.25 N

Tension in the string is 12.25 N

Answer 2

Answer:

Given :-

Mass = 1 kg

string = 1 m

Radius of circle = 0.6 m

To Find :-

Tension in string

Solution :-

We know that

sinθ = √1 - cos²θ

Here,

cosθ = 0.6 m

√1 - [(0.6)/1]²

√1 - (0.36)/1

√1 - 0.36

• √1 = 1

1 - 0.36

0.64

Tsinθ = mg

T × 0.8 = 1 × 9.8

0.8T = 9.8

T = 9.8/0.8

T = 12.25 N