A small object of uniform density rolls up a curved surface with an initial velocity v it reaches up to a maximum height of 3v^2/4g with respect to the initial position the object is
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Secondary School
Physics
5 points
A small object of uniform density rolls up a curved surface with an initial velocity v it reaches upto a maximum height of 3v²/4g with respect to the initial position. What is the object
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byShekhartholia21 03.05.2018
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Me · Beginner
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kakkarvaishnavi
Helping Hand
From the law of conservation of energy,
mgh = 1/2mv² + 1/2 Iω²
I = mk²(where, k= radius of gyration) and, ω = v²/r²
by solving the eq.,
v²= 2gh/1+(k²/r²)
put 'h' = 3v²/4g in this eq. and by solving, you'll get,
k²/r² = 1/2
which means, given object is a DISC
Secondary School
Physics
5 points
A small object of uniform density rolls up a curved surface with an initial velocity v it reaches upto a maximum height of 3v²/4g with respect to the initial position. What is the object
Ask for details
Follow
Report
byShekhartholia21 03.05.2018
Answers
Me · Beginner
Know the answer? Add it here!
kakkarvaishnavi
Helping Hand
From the law of conservation of energy,
mgh = 1/2mv² + 1/2 Iω²
I = mk²(where, k= radius of gyration) and, ω = v²/r²
by solving the eq.,
v²= 2gh/1+(k²/r²)
put 'h' = 3v²/4g in this eq. and by solving, you'll get,
k²/r² = 1/2
which means, given object is a DISC
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