A small object of uniform rolls up a curved surface with an initially velocity 'v'. It reaches upto a maximum height of 3v24g with respect to the initial position. The object is -
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answer 》》A small object of uniform rolls up a curved surface with an initially velocity 'v'. It reaches upto a maximum height of 3v24g with respect to the initial position. The object is DISC
Full Solution 》》》
From the law of conservation of energy,
mgh = 1/2mv² + 1/2 Iω²
I = mk²(where, k= radius of gyration) and, ω = v²/r²
by solving the eq.,
v²= 2gh/1+(k²/r²)
put 'h' = 3v²/4g in this eq. and by solving, you'll get,
k²/r² = 1/2
which means, given object is a DISC
Hope helped ♥♥♥
★★ HERE IS YOUR ANSWER ★★★
answer 》》A small object of uniform rolls up a curved surface with an initially velocity 'v'. It reaches upto a maximum height of 3v24g with respect to the initial position. The object is DISC
Full Solution 》》》
From the law of conservation of energy,
mgh = 1/2mv² + 1/2 Iω²
I = mk²(where, k= radius of gyration) and, ω = v²/r²
by solving the eq.,
v²= 2gh/1+(k²/r²)
put 'h' = 3v²/4g in this eq. and by solving, you'll get,
k²/r² = 1/2
which means, given object is a DISC
Hope helped ♥♥♥
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