Physics, asked by anishpraharsha6112, 10 months ago

A small photocell is placed at a distance of 4 m from a
photosensitive surface. When light falls on the surface the
current is 5 mA. If the distance of cell is decreased to 1 m,
the current will become
(a) 1.25 mA (b) (5/16)mA
(c) 20 mA (d) 80 mA

Answers

Answered by shakiya88

1

80 mA is correct answer..

may this helpful..

please mark it brainliest..

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