Question

A small piece of wire bent into an L shape with upright and
horizontal portions of equal lengths, is placed with the
horizontal portion along the axis of the concave mirror whose
radius of curvature is 10 cm. If the bend is 20 cm from the
pole of the mirror, then the ratio of the lengths of the images
of the upright and horizontal portions of the wire is
(a) 1:2
(b)3:1
(c) 1:3
(d) 2:1​

Answer 1

Answer:

Hope this helps you.......................

Explanation:

Focal length of mirror f=R2=102=5cm  For part PQ : transverse magnification length of image L1 = (ff−u)×L0 = (−5−5−(−20))×L0=−L03 For part QR : longitudinal magnification                    Length of image L2=(ff−u)2L0            = (−5−5−(−20))2×L0=L09 Þ L1L2=31

Answer 2

Answer:

1.2

Explanation:

as we take 10/20 its ratio willbe1.2