Question

A small stone of mass m (= 200 g) is held under water in a tall jar and is allowed to fall as shown in figure. The forces acting on stone are also shown. (i) What does F₂ represent?
(ii) What does m₁ represent?
(iii) What is the net force acting on stone?
(iv) What is the acceleration of stone as it falls through water? Neglect the force due to viscosity. Assume that the volume of stone = 80 cm³, density of water = 1.0 g cm⁻³ and acceleration due to gravity g = 10 ms⁻².

Answer 1

Answer:

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Explanation:

F represents the upthrust on stone due to water

V m, represents the mass of water displaced stone

by

is Net force acting on stone = F - F, (downwards) iy Given V 80 cm. p=ig cm g= 10 m

m = 200 g 200 1000 kg = 0-2 kg

weight of stone F= mg = 02 kg x 10 ms=2 N Mass of water displaced m = Vp = 80 x1 = 80 g

80 1000 kg = 0-08 kg upthrust F, = mg = 0.08 kg x 10 ms=08 N

Hence net downward force on stone

= F,-F = 2-08 = 1-2 N

Force

12N

Acceleration = = 6 ms?

Mass 0-2 kg