A small village having a population of 5000,requires 75L of water per had per day the village has got an over had tank of measurment 40m×25m×15m.for how many days will the water of this tank lost.
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Total volume of water in the tank
=40×25×15
=15000m^3
but,1m^3=1000l
so total amount of water is 15000×1000=15000000
no.of days=volume of water/water used per day
=15000000/5000×75
=40 days
=40×25×15
=15000m^3
but,1m^3=1000l
so total amount of water is 15000×1000=15000000
no.of days=volume of water/water used per day
=15000000/5000×75
=40 days
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