A smooth ball of mass m strikes a horizontal surface with a velocity v in a
direction making an angle 30° with the normal to the surface as shown in the
figure. If the coefficient of restitution for the collision between the ball and
the surface is e and the ball was in contact with the surface for a small time
'At', the average force acting on the ball during collision is
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Answer:
Force = rate of change of momentum
Intial velocity components= √3 v÷2 i + v÷2 j
After collision the components becomes= √3 e v ÷2 i + v÷2 j
Change in velocity = √3v(e-1)÷2 i
Change in momentum = m×√3v(e-1)÷ 2
As time t is small, let it be t ,rate of change of momentum = m×√3v(e-1)÷2t
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