Question

A smooth ring p of mass m can slide on a fixed smooth horizontal rod. A string tied to the ring passes over a fixed pulley and carries a block q of mass (m/2) as shown in the fig. At an instant, the string between the ring and the pulley makes an angle 60º with the rod. The initial acceleration of the ring , if the system is released from rest is

Answer 1

The initial acceleration of ring is g/6.

Explanation:

Consider a' be the initial acceleration of the ring

For ring :    Tcos(60°) = ma'  = m( a cos)60°)

T  = ma  

For block:

m /2 a = mg /2 - T

m/2 a = mg/2 - ma

a = g /3

Initial acceleration of ring a'= g/3 x 1/2 = g/6

Thus the initial acceleration of ring is g/6.

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Answer 2

Explanation:

The main thing is the that the component of real acc is taken