Question

A smooth wooden block is placed on a smooth wooden tabletop. You must exert a 14.0N force to keep the 40.0N block moving at constant velocity.
a. What is the coefficient of sliding friction?
b. If a 20.0N brick is placed on the block, what force will be required to keep the block and brick moving at constant velocity?

Answer 1

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Answer 2

Given:

W = -75 N g

= -9.8 m/s 2

W = mg → m = W/g m

= -75N/-9.8 m/s 2 m = 7.7 kg

Force and Acceleration Force and Acceleration

Since the question is asking for acceleration, we need to use Newton’s 2 nd Law,

F net = ma

Given: W = -75 N

Upward force = 90 N m = 7.7 kg

F net = ma →

a = F net /m a = (-75 N + 90 N)/7.7 kg a = 15 N/7.7 kg a = 1.9 m/s 2