a snail's on the Everage Creeps 75 cm of up a vertical pole during 12 hours in the night and slips down 40 cm during 12 hours in the day .in what short time will it reach the top of the pole of 5 m 5 cm height
Answers
Answer:
Answer: I have two answers.. check which is right
82.4 hours
or
88 hours
Step-by-step explanation:
If the question was how long will it take to climb the rest of the poIe this is the answer
snails current position is (75-40) = 35cm
time taken to climb 75 cm = 12 hours
so one hour can also be written as 60 min
so time taken to climb 1 cm= 12*60/75
= 720/75 = 9.6
so to climb 5.15 m it takes
9.6*515 = 4944
so it takes 4944 min to climb the rest of the poIe
so therefore it takes
4944/60 hrs to climb.... ie
82.4 hrs
.
If the question was how long it takes to climb the complete poIe the answer will be
(steps are same from above till time taken to climb 1 cm)
so we know it takes 9.6 min. so
time taken to climb the poIe will be
The height of the poIe * time taken to climb a cm
so convert 5.5 m to cm and it will be 550 cm
therefore we get the equation
550*9.6= 5280 min
and time taken(in hours) will be
5280/60 = 88 hours
So it takes 88 hours to climb the complete
Step-by-step explanation: