Question

A soap bubble is charged to a potential of 16v. its radius is then doubled. the potential of the bubble now will be:

Answer 1

V = q/C = qK/r

V1 = qK/r = 16 V ----------> equation 1

V2 = qK/2r ----------> equation 2

Dividing equation 1 by equation 2

V1/V2 = 2r/r = 2

V2 = V1/2

V2 = 16/2

V2 = 8 V.

Answer 2

Explanation:

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