Question

a social welfare association decide to supply drinking water which in the shape of cylinder with hemisperical ends length is 4.2m and the diameter of base is 1.2m find the volume​

Answer 1

The volume of the drinking water tank is  4.295 m³ or 4295 litres.

Step-by-step explanation:

The length of water tank = 4.2 m

The diameter of the base of the cylinder, d = 1.2 m

So, the radius, r = d/2 = 1.2/2 = 0.6 m

∴ The length of the cylindrical portion of the tank, h = 4.2 - 1.2 = 3 m

Now,

The volume of the cylindrical portion is,

= πr²h

= $\frac{22}{7}$ × 0.6² × 3

= 3.39 m³

and

The volume of the 2 hemispherical ends is,

= 2 × [$\frac{2}{3}$ πr³]

= $\frac{4}{3}$ × $\frac{22}{7}$ × 0.6³

= 0.905 m³

∴ The volume of the drinking water tank is given by,

= [ volume of the cylindrical portion] + [volume of the 2 hemispherical ends]

= 3.39 m³ + 0.905 m³

= 4.295 m³

∵ 1 m³ = 1000 litres

∴ 4.295 m³ = 4.295 × 1000 = 4295 litres

Thus, the volume is 4.295 m³ or 4295 litres.

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Answer 2

Answer:

Step-by-step explanation:

The length of the water tank = 4.2 m

The diameter of the base of the cylinder and the two hemispherical ends, d = 1.2 m

So, the radius, r = d/2 = 1.2/2 = 0.6 m

 

∴ The length of the cylindrical portion of the tank, h = 4.2 - 1.2 = 3 m

Now,  

The volume of the cylindrical portion is,

= πr²h  

=  × 0.6² × 3

= 3.39 m³

and

The volume of the 2 hemispherical ends is,

= 2 × [ πr³]

=  ×  × 0.6³

= 0.905 m³

∴ The volume of the drinking water tank is given by,

= [ volume of the cylindrical portion] + [volume of the 2 hemispherical ends]

= 3.39 m³ + 0.905 m³

=  4.295 m³

= $\frac{ 4.295 }{1000}$ =  4295 litters

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