Math, asked by raghu181raghu, 11 months ago

a social welfare association decided for supply water for affected people.the drinking water is filled ina water tanker which is in the shape of cylinder with hemispherical end as shown in figure .the whole length of the tanker is 4.2m and diameter of base of the cylinder and two hemispheres are each 1.2m.if they distribute drinking water to 60 people in a container each is in the shape of cylinder of radius 21 cm and height 50 cm, find the quantity of water left in the tanker after distribution in litre.​

Answers

Answered by vivekanand52
2

The volume of water left in the tank will be = 11230 liters.

Step-by-step explanation:

The length of the cylindrical part of the water tank is (4.2 - 1.2 - 1.2) = 1.8 m.

Now, the volume of water in the water tank will be = \pi r^{2}l + \frac{4}{3} \pi r^{3}

= \frac{22}{7} \times 1.2^{2} \times 1.8 + \frac{4}{3}\times \frac{22}{7}\times (1.2)^{3}

= 15.387 m³

Now, the 60 people have cylindrical container and volume of each will be

πr²h = \frac{22}{7}\times 21^{2}\times 50 = 69300 cm³ = 0.0693 m³

Therefore, the volume of water left in the tank will be = (15.387 - 60× 0.0693) = 11.23 m³ = 11230 liters. (Answer)

Answered by psupriya789
0

Answer:

Quantity of water left in the tanker = 1,499 litters

Step-by-step explanation:

The quantity of water left in the tanker after distribution = Total quantity - Distributed quantity

Total quantity = Volume of the tanker

Volume of the cylinder of 4.2 m length and 1.2 m of a diameter.

Volume of cylinder = π r² L

(given L = 4.2m and diameter = 1.2m)

Substituting, we get Volume (cylinder) = 22/7 * 0.6 * 0.6 * 4.2 = 4.752 m³

Volume of 2 hemispheres at the end = 2* 2πr³/3  = 4 * 22/7 * (0.6)³ / 3 = 792 / 875 m³

Volume of tanker =  4.752 + 792/875 =  5.657 m³

Distributed quantity = 60 times the volume of a cylinder of radius 21 cm and height is 50 cm

= 60 * πr²L

= 60 * 22/6 * 21² * 50

=  4,158,000 cm³

= 4.158 m³

The quantity of water left in the tanker after distribution = 198/35 - 4.158 = 1.499 m³

1 m³= 1,000 litter

So quantity of water left in the tanker after distribution = 1.499 * 1000 = 1499 litters

hope it  helps u

thanks :)

MARK AS BRAINLIEST

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