A Social Welfare Association decides to supply
drinking water for the flood affected people
the drinking water is filled in a water tanker
which is in the shape of a cylinder with
hemispherical ead as shown in fig the
Whole length of the tank is 4.2 Metore and
diameter of base of the cylinder and two bemi-
-spheres are each 1-2m . If they distribute
drinking water to 60 people in a container
each is in the shape of cylinder radius 21 cm
and beight som find the quantity of water
left in the tanker after distribution in
litre.
Answers
vol of tank= vol of cylinder + vol of 2 hemisphere
convert this answer into cm3
vol of glass= vol of cylinder× 60
tAke vol of tank as eq 1 and vol of glass eq2
subtract 1 & 2
divide the answer by 1000
then answer will be 141.42 l
Step 1:
The length of the water tank = 4.2 m
The diameter of the base of the cylinder and the two hemispherical ends,
d = 1.2 m
So, the radius, r = d/2 = 1.2/2 = 0.6 m
∴ The length of the cylindrical portion of the tank, h = 4.2 - 1.2 = 3 m
Now,
The volume of the cylindrical portion is,
= πr²h
= × 0.6² × 3
= 3.39 m³
and
The volume of the 2 hemispherical ends is,
= 2 × [ πr³]
= × × 0.6³
= 0.905 m³
∴ The volume of the drinking water tank is given by,
= [ volume of the cylindrical portion] + [volume of the 2 hemispherical ends]
= 3.39 m³ + 0.905 m³
= 4.295 m³
Step 2:
The dimension of the small cylindrical containers:
Radius, r = 21 cm = 0.21 m
Height, h = 50 cm = 0.5 m
The no. of people to whom the drinking water was distributed in cylindrical containers = 60
∴ The volume of water distributed to 60 people is given by,
= 60 * [Volume of the cylindrical containers]
= 60 * [πr²h]
= 60 * (22/7) * 0.21² * 0.5
= 4.158 m³
Step 3:
Therefore,
The quantity of water left in the tanker after the distribution is given by,
= [volume of the drinking water tank] – [volume of water distributed to 60 people]
= 4.295 m³ - 4.158 m³
= 0.137 m³
∵ 1 m³ = 1000 litres
= 137 litres