Question

A sodium salt on treatment with mgcl2 gives white precipitate only on heating.the anion of sodium salt is

Answer 1

Explanation:

The sodium salt used could be sodium bicarbonate, $NaHCO_{3}$. Therefore, when sodium bicarbonate reacts with magnesium chloride then it results in the formation of magnesium carbonate which is a white precipitate and sparingly soluble.

The reaction will be as follows.

    $2NaHCO_{3} + MgCl_{2} \rightarrow MgCO_{3} + 2NaCl + H_{2}O + CO_{2}$