Math, asked by nagasai8583, 11 months ago

A software comp was advertised to recruit people with exposure to C and
C++. 241 applications were received and on sorting out it was found that 40 of
them dont have exposure to c and c++. 180 of them had exposure to c and 186 of
them had exposure to c++ .how many of them had exposure to c only

Answers

Answered by assalterente
4

Answer:

Step-by-step explanation:

Our question is: A software comp was advertised to recruit people with exposure to C and  C++. 241 applications were received and on sorting out it was found that 40 of them dont have exposure to c and c++. 180 of them had exposure to c and 186 of  them had exposure to c++ .how many of them had exposure to c only.

Firstly, let t = 241 be the total number of applicants.

Also we will consider x = 40 the number of applicants with no exposure to c and c++, a = 180 the number of applicants with exposure to c and b = 186 with exposure to c++.

Lets say c is the number of applicants who had exposure to c only.

241 - 40 = 201 is the number of applicants who have exposure to at least one of c or/and c++.

201  - 186 = 15 is the number of applicants who do not have exposure to c++.

Hence we can conclude that the number of applicants who had exposure to c only is 15.

I hope this answer helped you! Good studies!!

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